SELECT H.hacker_id, H.name
FROM Submissions S
INNER JOIN Challenges C ON S.challenge_id = C.challenge_id
INNER JOIN Difficulty D ON C.difficulty_level = D.difficulty_level
INNER JOIN Hackers H ON S.hacker_id = H.hacker_id
WHERE S.score = D.score AND C.difficulty_level = D.difficulty_level
GROUP BY H.hacker_id, H.name
HAVING COUNT(H.hacker_id) > 1
ORDER BY COUNT(H.hacker_id) DESC, H.hacker_id
'데이터수집 > Mysql' 카테고리의 다른 글
Mysql CRUD 연습_1 (0) | 2021.09.06 |
---|
댓글